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n200080 [17]
3 years ago
8

Find the value of y when x = -10/3, If

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0
Plug it in
y = 2/3(24 - -10/3) + 5(-10/3)y
y = 2/3 (82/3) + 5(-10/3)y
y = 164/9 - 50/3y
because there are “y” values on both sides, they cancel out, leaving a number to equal another number. this does not make any sense. therefore, there is no solution to this equation when x = -10/3.
Serggg [28]3 years ago
7 0

Answer:

I think y= 12/53

Step-by-step explanation:

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nevsk [136]

Answer:

1, 2, 4

Step-by-step explanation:

  1. 4 1/12·2 2/3 = 49/12·11/4 = 49/12·33/12 = 1617/144 = 11 11/48 Good
  2. 2 1/5·6 1/4 = 11/5·25/4 = 44/20·125/20 = 5500/400 = 13 3/4 Good
  3. 1 1/2·3 1/5 = 3/2·16/5 = 15/10·32/10 = 480/100 = 4.8 Doesn't Work
  4. 3/4·8 1/5 = 3/4·41/5 = 15/20·164/20 = 2460/400 = 6 3/20 Good
  5. 5 1/2·5 = 11/2·5 = 55/2 = 27 1/2 Doesn't Work

(Note: Division of big numbers should be done by simplification, although not shown here.)

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Which of the following is the correct factored form for the given equation? 2x^2+8x+6=0
3241004551 [841]
It would be 2(x+3)(x+1)=0

Explanation:
I used factor by grouping. You multiply the first term (2) by the last term (6). This gives you 12 then take the factors of 12 that add up to the middle term 8. You get 6 and 2.
It should look like 2x^2+6x+2x+6=0
when you do factor by grouping you factor the first two terms and then the last two terms separately. So you get (2x+2) and (x+3). (2x+2) could be factored into 2(x+1). Then you put everything together and get 2(x+3)(x+1)=0
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