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DanielleElmas [232]
3 years ago
9

Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this problem. A cube-shaped contain

er has an edge length of 23 feet. What is the volume of the container?
Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0
12167 feet squared.......
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Which of these answers is closest to zero-2, 0.2, 1, 1/2
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0.2 is closest to zero
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What inequality represents the following sentence?
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Find M<1, M<2, M<3, M<4, M<5
Leokris [45]

Answer:

Step-by-step explanation:

m∠2 = 52° [Alternate interior angles]

m∠1 + m∠2 = 180° [Linear pair of angles are supplementary]

m∠1 = 180° - 52°

m∠1 = 128°

m∠3 = 47° [Alternate interior angles]

m∠5 + 52° + 47° = 180° [Sum of linear angles is 180°]

m∠5 = 180° - 99°

        = 81°

m∠4 + 47° = 180° [Sum of consecutive interior angles is 180°]

m∠4 = 180° - 47°

m∠4 = 137°

6 0
3 years ago
The average sea-level in 1900 at London-bridge was 33 feet. In 1990 it was 33.08 feet. Use linear interpolation or extrapolation
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7 0
3 years ago
The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi
slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

So the correct option is 4

8 0
3 years ago
Read 2 more answers
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