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Aleksandr-060686 [28]
3 years ago
7

Which shows one way to determine the factors of x^3+4x^2+5x+20

Mathematics
1 answer:
bonufazy [111]3 years ago
8 0
X^2(x+4)+5(x+4)

(x^2+5)(x+4)

the answer to the question
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Go to the website below this messages for the answer with step-bij-step explanation

Step-by-step explanation:

https://socratic.org/questions/how-do-you-simplify-b-a-b-a-a-b

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How do I solve %15 of 240
Black_prince [1.1K]

Answer:

36

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Kamila [148]

Answer:

\frac{28-3i}{26}

Step-by-step explanation:

For #2, remember that i=\sqrt{-1}, so i^{2}=-1 Also, (a+b)(a-b), where a and b are any numbers, (a+b)(a-b)=a^2-b^2. Now, to simplify, or radicalize, a number with surds in the denominator, you have to multiply the denominator by its conjugate. If there is a complex number a+bi, where a and b are any numbers, the conjugate is always a-bi. Lets apply these rules. The conjugate of 4+6i is 4-6i, so do this:

\frac{5+6i}{4+6i}=\frac{(5+6i)(4-6i)}{(4+6i)(4-6i)}=\frac{20+24i-30i+36}{16+36}=\frac{56-6i}{52}=\frac{2(28-3i)}{2(26)}=\frac{28-3i}{26}

Our answer is (28-3i)/(26)!

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(0.5n+0.3)-(0.75n-0.45) find answer
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I believe your answer is -0.25n+0.75
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