Step-by-step explanation:
y= 1
when x=2
here
when x= 3
y=4
Δ=88
1) Using the Quadratic Equation to Solve
3x²-8x+1=3
3x²-8x+1-3=3-3
3x² -8x -2=0
2)Let's find the discriminant
Δ= (-8)²-4(3)(-2)
Δ=64 -4(3)(-2)
Δ=88
(cos(x) + cos(y))^2 + (sin(x) - sin(y))^2 Remove the brackets
cos^2(x) + cos^2(y) + 2cos(x)*cos(y) + sin^2(x) - 2(sin(x)*sin(y) + sin^2(y) Combine these two in bold to make 1 because sin^2(x) + cos^2(x) = 1
1 + cos^2(y) + 2cos(x)*cos(y) - 2*sin(x)*cos(y) + sin^2(y)
These two in bold also make 1
2 + 2cos(x)*cos(y) - 2*sin(X)*sin(y) Bring out a common factor of 2
2 +2(cos(x)*cos(y) - sin(x)*sin(y) )
but cos(x+y ) = cos(x)*cos(y) - sin(x)*sin(y)
2 + 2* cos(x + y) is your final answer.
Answer:
4 ( 8 - 2 ) = (-3) + 7 -> this is a false statement
Step-by-step explanation:
4 ( 8 - 2 ) = ( -3 ) + 7
Simplify the parenthesis
4 ( 6 ) = (-3) + 7
Multiply;
24 = (-3) + 7
Add, remember, adding a negative number and a positive number is the same as subtracting the negative number from the positive number,
24 = 4
This statement is not true.
thats true... why did you ¨ask a question¨"thats not a question?
