Plug the y value in
2(4)^3
Evaluate exponents first (order of operations)
2(64)
Multiply
128
Final answer: 128
r are increasing and s are increasing, therefore the second graph or third graph. For r = 0 → s = 10.
Therefore your answer is second graph.
Answer:
Step-by-step explanation:
we know that
The area of a regular hexagon is the same that the area of 6 equilateral triangles
The area of 6 equilateral triangles applying the law of sines is equal to
![A=6[\frac{1}{2}b^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7Db%5E2sin%2860%5Eo%29%5D)
where
b is the length side of the regular hexagon
we have
substitute
![A=6[\frac{1}{2}(10)^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%2810%29%5E2sin%2860%5Eo%29%5D)
Answer:
The space between each value on the scale of a bar graph is called an interval. In other words, the interval is the relation between the units you're using, and their representation on the graph, or the distance between marks. You choose intervals based on the range of the values in the data set.^-^
Step-by-step explanation:
Hoped I Have Helped Have Nice Day "Peace"
Answer:
infinite points along the line
Step-by-step explanation:
This is the equation for a line. A line has infinite points. So there are infinite solutions along the line
