Problem: Total of Leiff's online purchase
Given: $ 128 for video game
5.3% discount price of the video game
$4.75 shipping fee
15% promotion for more the $50 orders
Solution:
<span>Total = [(85% x 128 )+ (5.3% x 85% x 128) + 4.75]
</span>= 108.80 + 5.78 + 4.75
= <span>$119.32</span>
Answer:
This is the table that the question is referring to:
Price QJ QS
5 4 2
10 3 1
15 2 0
20 1 0
Total market demand is the sum of the individual market demands. In this market, it is the sum of the market demand of Jake and Sue.
Market demand at the price of $5 is 7 pizzas.
Market demand at the price of $10 is 4 pizzas.
Market demand at the price of $15 is 2 pizzas.
Market demand at the price of $20 is 1 pizza.
<span><span>Economy- Macroeconomic conditions affect labor supply and demand. Job losses during a recession mean less disposable income for consumers and less demand for cars.</span>
<span>Globalization-Globalization involves the import of foreign automobiles and relocation of manufacturing facilities overseas. This has led to a steady decline in U.S. automobile-sector employment.</span>
<span>Compensation- Compensation includes wages and benefits. According to an April 2011 U.S. Bureau of Labor Statistics report, there has been upward pressure on wages and downward pressure on benefits.</span>
</span>
Answer:
It will take 30.10 year
Explanation:
We have given initial investment $500000
Future value = $ 1 million = $1000000
Rate of interest r = 1.79 %
We have to find the time taken to reach the amount $1000000
We know that future value is equal to ![A=P(!+\frac{r}{100})^n](https://tex.z-dn.net/?f=A%3DP%28%21%2B%5Cfrac%7Br%7D%7B100%7D%29%5En)
![1000000=500000(!+\frac{1.79}{100})^n](https://tex.z-dn.net/?f=1000000%3D500000%28%21%2B%5Cfrac%7B1.79%7D%7B100%7D%29%5En)
![2=(1.0179)^n](https://tex.z-dn.net/?f=2%3D%281.0179%29%5En)
Taking log both side
![log2=nlog1.0179](https://tex.z-dn.net/?f=log2%3Dnlog1.0179)
n×0.0077 = 0.3010
n = 39.09 year
Now in second case rate of interest
r = 2.34 %
So ![1000000=500000(1+\frac{2.34}{100})^n](https://tex.z-dn.net/?f=1000000%3D500000%281%2B%5Cfrac%7B2.34%7D%7B100%7D%29%5En)
![2=(1+\frac{2.34}{100})^n](https://tex.z-dn.net/?f=2%3D%281%2B%5Cfrac%7B2.34%7D%7B100%7D%29%5En)
![2=1.0234^n](https://tex.z-dn.net/?f=2%3D1.0234%5En)
taking log both side
log 2 = n log 1.0234
n×0.01 = 0.3010
n = 30.10 year