Your function is

. The fundamental theorem of algebra says that there will be three roots, since the degree of the polynomial is 3. The problem provides two real roots, x = -2 and x = 3, so there must be one more.
The theorem also says that possible roots of the polynomial would be in this case, the factors of the constant (-6) over the factors of the coefficient of the term with the highest degree (1).
Factors of -6 are: 1, 2, 3, 6, -1, -2, -3, -6
Factors of 1 are: 1, -1
Possible rational roots are: 1, 2, 3, 6, -1, -2, -3, -6
I then use synthetic division to see which possible rational root is a real root by dividing

by the possible rational roots, and I get a root when the remainder is 0. Remember to put the placeholder of 0 for x^2 when dividing:
-1} 1 0 -7 -6
-1 1 6
-----------------
1 -1 -6 0
When I divide by the possible rational root of -1, I get a remainder of 0, which means -1 is a root.
To check:
(x + 2)(x - 3)(x + 1)
= (x^2 - x - 6)(x + 1)
= x^3 - x^2 - 6x + x^2 - x - 6
= x^3 - 7x - 6
I think this is asking what power when the first number given is raised to it will equal the number within the parentheses. So, for example, the answer to the first question would be 5 because 2^5 = 32. 10^3 = 1000, so the answer is 3, and so on.
Answer:
Step-by-step explanation:
Answer:
B) 5 x 4 x 3 x 2 x 1
Step-by-step explanation:
When you see a ! directly next to a number (such as 5!), it means that you are multiplying starting from that number, and stepping down each time:
5! = 5 * 4 * 3 * 2 * 1
For example, take factoral 10: 10!
10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3,628,800
In this case, you are multiplying 5!.
5! = 5 * 4 * 3 * 2 * 1 = (20) * (6) * 1 = 120
5! = 120