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vlabodo [156]
3 years ago
8

URGENT URGENT HELP In what direction and by how many units is the graph of f(x) = 6 sin(2x + π) − 5 vertically and horizontally

shifted?
Mathematics
2 answers:
Kazeer [188]3 years ago
5 0

Answer:

The required result is 5 unit vertically shifted downward and \frac{\pi}{2} unit horizontally shifted left.

Step-by-step explanation:

Given : Graph f(x) = 6\sin(2x+\pi)-5

To find : In what direction and by how many units is the graph vertically and horizontally shifted?

Solution :

Vertically shift is up or down,

Vertically shifting down is shifting outside the function,

i.e, f(x)→f(x)-b

In the given graph, The graph is 5 unit vertically shifted downward as

f(x) = 6\sin(2x+\pi)-5 i.e, 5 unit shifted downward.

Horizontal shift is either left or right,

Horizontally shift left is shifting inside the function,

i.e,  f(x)→f(x+b)

We can write the given function as f(x) = 6\sin(x+\frac{\pi}{2})-5

In the given graph, The graph is \frac{\pi}{2} unit horizontally shifted left as

f(x) = 6\sin(x+\frac{\pi}{2})-5 i.e, \frac{\pi}{2} unit shifted left.

Therefore, The required result is 5 unit vertically shifted downward and \frac{\pi}{2} unit horizontally shifted left.

iris [78.8K]3 years ago
4 0
<span>A. Down 5, Left pi/2</span>
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Answer:

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Problems of normally distributed samples are solved using the z-score formula.

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Z = \frac{X - \mu}{\sigma}

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And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have \mu = 43, \sigma = 4

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 43}{4}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

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If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

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