Answer:
h = 4.04 m
Explanation:
Given that,
Mass of a child, m = 25 kg
The speed of the child at the bottom of the swing is 8.9 m/s
We need to find the height in the air is the child is able to swing. Let the height is h. Using the conservation of energy such that,

Put all the values,

So, the child is able to go at a height of 4.04 m.
This is something I have no idea
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This problem is pretty straight forward since we are given
the half time and we simply have to find for the rate constant. The equation
relating the two variable is:
t1/2 = ln(2) / k
where k is the rate constant, therefore:
k = ln(2) / t1/2
k = ln(2) / 14.7 h
<span>k = 0.047 / hour</span>