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Blababa [14]
2 years ago
10

How does the use of renewable sources of energy help to solve the problem of energy

Physics
1 answer:
trasher [3.6K]2 years ago
8 0

Answer:

The use of renewable sources of energy help to solve the problem of energy  crisis is discussed below in details.

Explanation:

Environmental and economic advantages of adopting renewable energy incorporate: Creating energy that originates no greenhouse gas discharges from fossil fuels and decreases some kinds of air pollution. Increasing energy stocks and decreasing dependency on shipped fuels.

Here are 5 actionable suggestions you can follow to make a decent utilization of renewable energy on your bases:

  • Embrace Solar-Powered Technologies.
  • Crowdfund Clean Energy Projects.
  • Establish the Society of Concerned Scientists.

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This is 8th grade science plz help
borishaifa [10]

The parents genotypes can be described as incomplete dominance since each parent provides a different allele of the given gene and none is dominating.

Heterozygous genotype is a process where by an offspring inherits different forms of a particular gene from each parent. .

Looking at the Punnett square, it is oblivious that the offspring inherited different version of the parents genes. This is shown by the presence of the two different letters indicated as Tt for all the four boxes in the Punnett square.

Thus, we can conclude that each parent provides a different allele of the given gene and none of the parents gene is dominating.

Learn more here: brainly.com/question/14671992

3 0
3 years ago
When fuel and air are compressed in the compression stroke, ...... a. each molecule of fuel is heated to its flash point b. each
alexira [117]

None of the choices is an appropriate response.

There's no such thing as the temperature of a molecule.  Temperature and
pressure are both outside-world manifestations of the energy the molecules
have.  But on the molecular level, what it is is the kinetic energy with which
they're all scurrying around.

When the fuel/air mixture is compressed during the compression stroke,
the temperature is raised to the flash point of the mixture.  The work done
during the compression pumps energy into the molecules, their kinetic
energy increases, and they begin scurrying around fast enough so that
when they collide, they're able to stick together, form a new molecule,
and release some of their kinetic energy in the form of heat.


7 0
3 years ago
Starting from the front door of your ranch house, you walk 50.0 m due east to your windmill, and then you turn around and slowly
Hunter-Best [27]

Answer:

Average velocity

v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}

Average speed,

S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}

Explanation:

(a)Average velocity

We have to find the average velocity. We know that velocity is defined as the rate of change of displacement with respect to time.

To find the average velocity we have to find the total displacement.

since displacement along east direction is 50m

and displacement along west=40m

so total displacement,

d=50m-40m\\d=10m

total time,

t=28 s+42 s\\t=70 s

therefore, average velocity

v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}

(b)Average Speed:

Average speed is defined as the ratio of total distance to the total time

it means

Average speed= total distance/total time

here total distance,

D= 50m+40m\\D=90m

and total time,

t= 28s+40s\\t=70s

therefore,

Average speed,

S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}

8 0
3 years ago
Which word is not a good way to describe exercise?
Karolina [17]
In my opinion, calling exercise "work"  wouldn't be a good way of describing it, I don't think people would exercise if its called work 
3 0
3 years ago
A mass m = 550 g is hung from a spring with spring constant k = 2.8 N/m and set into oscillation at time t = 0. A second, identi
riadik2000 [5.3K]

Answer:

The second system must be set in motion t=0.70s seconds later

Explanation:

The oscillation time, T, for a mass, m, attached to spring with Hooke's constant, k, is:

T=2\pi\sqrt(\frac{m}{k} )

One oscillation takes T secondes, and that is equivalent to a 2π phase. Then, a difference phase of π/2=2π/4, is equivalent to a time t=T/4.

If the phase difference π/2 of the second system relative to the first oscillator. The second system must be set in motion t=\frac{\pi}{2}\sqrt(\frac{m}{k})=\frac{\pi}{2}\sqrt(\frac{0.55}{2.8}= 0.70s) seconds later

6 0
3 years ago
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