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3 years ago

15

Amit has found a rock in his backyard and would like to measure its mass, volume, and density. What tools can he use to perform

these measurements? A. meter stick, balance, and graduated cylinder B. graduated cylinder and balance C. meter stick and balance D. graduated cylinder and meter stick

1 answer:

Simora [160]3 years ago

7 0

A. Should be the correct answer:) hope this helped! :)

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Someone please help me will give BRAILIEST!!!!!

ratelena [41]

The speed increases, because as the angle increases (the wing slants up more steeply), the air has to go farther to get over the wing.

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3 years ago

A proton that has a mass m and is moving at 270 m/s in the i hat direction undergoes a head-on elastic collision with a stationa

Nataly_w [17]

Answer:

$V_p = 267.258 m/s$

$V_n = 38.375 m/s$

Explanation:

using the law of the conservation of the linear momentum:

$P_i = P_f$

where $P_i$ is the inicial momemtum and $P_f$ is the final momentum

the linear momentum is calculated by the next equation

P = MV

where M is the mass and V is the velocity.

so:

$P_i = m(270 m/s)$

$P_f = mV_P + M_nV_n$

where m is the mass of the proton and $V_p$ is the velocity of the proton after the collision, $M_n$ is the mass of the nucleus and $V_n$ is the velocity of the nucleus after the collision.

therefore, we can formulate the following equation:

m(270 m/s) = m $V_p$ + 14m $V_n$

then, m is cancelated and we have:

270 = $V_p$ + $14V_n$

This is a elastic collision, so the kinetic energy K is conservated. Then:

$K_i = \frac{1}{2}MV^2 = \frac{1}{2}m(270)^2$

and

Kf = $\frac{1}{2}mV_p^2 +\frac{1}{2}(14m)V_n^2$

then,

$\frac{1}{2}m(270)^2$ = $\frac{1}{2}mV_p^2 +\frac{1}{2}(14m)V_n^2$

here we can cancel the m and get:

$\frac{1}{2}(270)^2$ = $\frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2$

now, we have two equations and two incognites:

270 = $V_p$ + $14V_n$ (eq. 1)

$\frac{1}{2}(270)^2$ = $\frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2$

in the second equation, we have:

36450 = $\frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2$ (eq. 2)

from this last equation we solve for $V_n$ as:

$V_n = \sqrt{\frac{36450-\frac{1}{2}V_p^2 }{\frac{1}{2} } }$

and replace in the other equation as:

270 = $V_p +$ 14 $\sqrt{\frac{36450-\frac{1}{2}V_p^2 }{\frac{1}{2} } }$

so,

$V_p = -267.258 m/s$

Vp is negative because the proton go in the -i hat direction.

Finally, replacing this value on eq. 1 we get:

$V_n = \frac{270+267.258}{14}$

$V_n = 38.375 m/s$

3 0

3 years ago

A machine is classified as a compound machine when ___.

bearhunter [10]

Answer: it is made up two or more simple machines

Explanation: Brainliest Please!!!!

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3 years ago

A train pulls the boxcars. What are the vertical forces present? (1 point)

Greeley [361]

The vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.

The forces exerted on an object can be resolved into <em>horizontal</em> and <em>vertical components.</em>

<em />

The horizontal components of the forces on an object being pulled include the following;

The frictional force on the object; which tends to reduce the motion,

force dragging the object forward

if the object is inclined to an angle, the horizontal component of the weight

This horizontal force is written as;

$\Sigma F_x = 0\\\\F_x - F_k = ma$

The vertical component of the force on the object include the following;

the weight of the object acting downwards

the pull of air on the object acting upwards

The vertical force on the object is written as;

$\Sigma F_n = 0\\\\F_n - W = 0$

Thus, the vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.

Learn more here: brainly.com/question/2000189

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3 years ago

Explain why the reflection of light off ground glass changes from diffuse to specular if you spill water on it

Basile [38]

Because when you spill water on it, the reflection comes from the surface of the water, not the ground glass.

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3 years ago