Answer:
The correct answer is;
No, the quadrilateral is not always a parallelogram
Step-by-step explanation:
Since there are only four opposite angles in a quadrilateral there are only two possible angle bisectors of the opposite angles also, the angle bisectors of a pair of opposite angles of a quadrilateral will intersect within the quadrilateral and therefore they cannot form the sides of a parallelogram
Therefore, the answer is no, the quadrilateral is not always a parallelogram.
Answer:
a) 4(t - r) = 4(6 - 2.5) = 4 x 3.5 = 14
b) 4t - r = (4 x 6) - 2.5 = 24 - 2.5 = 21.5
c) 2(3t - 10) = 2(3 x 6 - 10) = 2(18 - 10) = 2 x 8 = 16
d) (t - 2)² = (6 - 2)² = 4² = 4 x 4 = 16
e) cannot decipher the equation
f) 6r + t = 6 x 2.5 + 6 = 15 + 6 = 21
P(t)=6t
A(p)=πp^2, since p(t)=6t
A(t)=π(p(t))^2
A(t)=π(6t)^2
A(t)=36πt^2, so when t=8 and approximating π≈3.14
A(8)≈36(3.14)(8^2)
A(8)≈36(3.14)64
A(8)≈7234.56 u^2
Answer:
Step-by-step explanation:
(12 - 2)/(2 - 7) = 10/-5 = -2
y - 12 = -2(x - 2)
y - 12 = -2x + 2
y = -2x + 14
C your welcome have a nice day
