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2 years ago

Fator the following problem x^2+12x+36

Mathematics

2 answers:

Mekhanik [1.2K]2 years ago

5 0

Answer:

(x-6)^2

Step-by-step explanation:

Hope this helped

user100 [1]2 years ago

4 0

Answer:

(x+6)2

Step-by-step explanation:1

What two numbers sum up to the middle term (6), and have a product of the last term (36)?

After some trial and error, we arrive at 6 and 6, which means we can factor this as

(x+6)(x+6) or (x+6)2

Another way we could have approached this is that we see that the leading term and the last term are both perfect squares.

With this in mind, we could rewrite the expression as

(x)2+12x+(6)2

Now, it becomes a little more clearer that we can factor this as

(x+6)2

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Step-by-step explanation:

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3 years ago

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lilavasa [31]

Answer:

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Step-by-step explanation:

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2 years ago

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Zigmanuir [339]

Answer:

A point and a line.

Further explanation:

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3 years ago

jada can write 3 1/4 pages in 8 minutes. At this rate, how many pages could jada write in 24 minutes?

makkiz [27]

Answer:

9 3/4 pages = x

Step-by-step explanation:

$\frac{pages}{minutes} = \frac{pages}{minutes}$ change 3 1/4 to a decimal

$\frac{3.25}{8} = \frac{x}{24}$

$3.25(24) = 8x$

$78 = 8x$

$\frac{78}{8} = x$

$9.75 = x$

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working with the fraction

3 1/4 /8 = x/ 24

3 1/4 (24) = 8x

13/4 (24) = 8x

316/4 = 8x

78 = 8x

78/8 = x

9 3/4 = x

7 0

2 years ago

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rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

3 years ago

Fator the following problem x^2+12x+36​

Fator the following problem x^2+12x+36