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Aleonysh [2.5K]
3 years ago
9

Multiple choice plz help!! Thank u!

Mathematics
2 answers:
lord [1]3 years ago
5 0
C your welcome have a nice day

iris [78.8K]3 years ago
3 0
The answer is A. The line AB cuts the circle in half. It's basically the middle line.
It's the diameter
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If 2a+3b=12 and ab=6 find the value of 8a^3+27b^3
Alex17521 [72]
<span>A) 2a + 3b = 12
B) ab = 6 solving for a
B) a = 6 / b then we substitute this into equation A)
</span><span>A) 12 / b + 3b = 12  </span><span>multiplying this by "b"
A) 12 + 3b^2 = 12b
A) 3b^2 -12b +12= 0 dividing by "3"
A) b^2 -4b + 4 = 0
Factoring
(b-2) * (b-2) = 0
b = 2
Since b = 2 then a = 3

</span>NOW, we put these numbers into:
<span>8a^3 +27b^3 </span>
8*3*3*3 + 27*2*2*2
216 + 216
The answer is 512


6 0
3 years ago
Read 2 more answers
Octavian became the emperor of Rome in 27 B.C. He ruled until his death in A.D. 14. How long did he rule as emperor?
frutty [35]

Answer:

He ruled about 40 years

6 0
3 years ago
Find the area of the following triangle:<br> b= 20, c = 15 , A=46
ikadub [295]

Answer:

a = 46

b = 20

c = 15

b+c ≤ a

20 + 15 ≤ 46

61 ≤ 46

Step-by-step explanation:

4 0
3 years ago
Please show work and thank youuu
Assoli18 [71]

Answer:  6\sqrt{3}

======================================================

Explanation:

Method 1

We can use the pythagorean theorem to find x.

a^2+b^2 = c^2\\\\6^2+x^2 = 12^2\\\\36+x^2 = 144\\\\x^2 = 144-36\\\\x^2 = 108\\\\x = \sqrt{108}\\\\x = \sqrt{36*3}\\\\x = \sqrt{36}*\sqrt{3}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 2

Use the sine ratio to find x. You'll need a reference sheet or the unit circle, or simply memorize that sin(60) = sqrt(3)/2

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(60^{\circ}) = \frac{x}{12}\\\\\frac{\sqrt{3}}{2} = \frac{x}{12}\\\\x = 12*\frac{\sqrt{3}}{2}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 3

Similar to the previous method, but we'll use tangent this time.

Use a reference sheet, unit circle, or memorize that tan(60) = sqrt(3)

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(60^{\circ}) = \frac{x}{6}\\\\\sqrt{3} = \frac{x}{6}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 4

This is a 30-60-90 triangle. In other words, the angles are 30 degrees, 60 degrees, and 90 degrees.

Because of this special type of triangle, we know that the long leg is exactly sqrt(3) times that of the short leg.

\text{long leg} = (\text{short leg})*\sqrt{3}\\\\x = 6\sqrt{3}\\\\

The short leg is always opposite the smallest angle (30 degrees).

3 0
2 years ago
I need help with this
NARA [144]

Answer:

all congruent

Step-by-step explanation:

5 0
3 years ago
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