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Alex777 [14]
3 years ago
14

Identify all values, if any, in the data set that would be considered outliers when creating a modified boxplot. 71 74 78 79 79

80 82
Mathematics
2 answers:
stich3 [128]3 years ago
7 0
None of those are really outliers because they are all fairly close to one another.
fiasKO [112]3 years ago
3 0

Answer:

No Outlier for the given data.

Step-by-step explanation:

The given set of data : 71, 74, 78, 79, 79, 80, 82

Before find the outliers, let's find the median, Lower quartile (Q1) and Upper quartile (Q3).

The given set of data is odd set of data.

So, median = Middle value of the data = 79

Q1 = Median of the lower part.

That is median of 71, 74, 78

So Q1 = 74

Now let's find Q3 which is median of the upper set of data 79, 80, 89

So Q3 = 80

Now let's find Outlier.

Outlier should be more than 1.5 times of Q1 and 1.5 times of Q3

1.5*Q1 = 1.5 * 74 = 111

1.5 Q3 = 1.5*80 = 120

There are no such numbers in the given data.

Therefore, No Outlier for the given data.

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Solve the simultaneous equations<br>4x+3y=1<br>4x^2+3xy+y^2=2​
Fantom [35]

Notice that the second equation,

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can be written as

<em>x</em> (4<em>x</em> + 3<em>y</em>) + <em>y</em> ² = 2

and the first equation says 4<em>x</em> + 3<em>y</em> = 1, so this reduces to

<em>x</em> + <em>y</em> ² = 2

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Solve for <em>x</em> :

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