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Alex777 [14]
3 years ago
14

Identify all values, if any, in the data set that would be considered outliers when creating a modified boxplot. 71 74 78 79 79

80 82
Mathematics
2 answers:
stich3 [128]3 years ago
7 0
None of those are really outliers because they are all fairly close to one another.
fiasKO [112]3 years ago
3 0

Answer:

No Outlier for the given data.

Step-by-step explanation:

The given set of data : 71, 74, 78, 79, 79, 80, 82

Before find the outliers, let's find the median, Lower quartile (Q1) and Upper quartile (Q3).

The given set of data is odd set of data.

So, median = Middle value of the data = 79

Q1 = Median of the lower part.

That is median of 71, 74, 78

So Q1 = 74

Now let's find Q3 which is median of the upper set of data 79, 80, 89

So Q3 = 80

Now let's find Outlier.

Outlier should be more than 1.5 times of Q1 and 1.5 times of Q3

1.5*Q1 = 1.5 * 74 = 111

1.5 Q3 = 1.5*80 = 120

There are no such numbers in the given data.

Therefore, No Outlier for the given data.

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6- 6x^2- 3x = 0 solve
VARVARA [1.3K]

Answer:

The solutions are x=\frac{3)+\sqrt{153} }{-12}, x=\frac{3)-\sqrt{153} }{-12}

If you need to have them in a decimal form rounded to 3 decimals, the answers would be x=-1.281, x=0.781

Step-by-step explanation:

We are given the equation 6-6x^2-3x=0

The first thing that can be done is to rearrange the terms so that they are in descending order of power. This makes it easier to work with

This gives us -6x^2-3x+6=0

To find the solutions to this equation, we can use the quadratic formula, which will tell us that the solutions are equal to \frac{-b+\sqrt{b^2-4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}

From our equation, we can gather that a=-6, b=-3, c=6

Now that we have our variables, we can plug them into the quadratic formula to get our solutions.

\frac{-(-3)+\sqrt{(-3)^2-4(-6)(6)} }{2(-6)}\\\\\frac{3)+\sqrt{9+144} }{-12}\\\\\frac{3)+\sqrt{153} }{-12}

And now for our second equation

\frac{-(-3)-\sqrt{(-3)^2-4(-6)(6)} }{2(-6)}\\\\\frac{3)-\sqrt{9+144} }{-12}\\\\\frac{3)-\sqrt{153} }{-12}

3 0
3 years ago
CAN SOMEONE HELP ME WITH THIS!!! IT IS TIMED
skelet666 [1.2K]

Answer: 2

Step-by-step explanation: Because 2 makes the denominator 0, which makes the entire thing undefined

6 0
3 years ago
In ∆ABC the angle bisectors drawn from vertices A and B intersect at point D. Find ∠ADB if: m∠С = γ
Rainbow [258]

Answer:

  90° + (γ/2)

Step-by-step explanation:

The angles in ΔADB have a sum of 180°, so ...

  (A/2) +(B/2) + ∠ADB = 180°

and so do the angles of ΔABC:

  A + B + γ = 180°

Dividing this second equation by 2 gives an expression for (A/2) +(B/2) that we can substitute into the first equation:

  A/2 +B/2 +γ/2 = 90°

  A/2 +B/2 = 90° -γ/2

Putting this in the first equation, we have ...

  (90° -γ/2) + ∠ADB = 180°

  ∠ADB = 90° +γ/2 . . . . . . . . . .  add (γ/2 -90°)

3 0
4 years ago
I just wanted to make sure what I'm doing is right
Olin [163]
You're doing it exactly right! Keep on going! :)
6 0
3 years ago
If you run 100 m and 9.99 seconds and someone else runs in 12.0 seconds how many meters would you have beat them by?
Vlad [161]

Answer:

Step-by-step explanation:

other runner runs in 12 seconds=100 m

runs in 9.9 seconds=100/12 ×9.9=990/12=330/4=165/2=82.5 m

you beat him by 100-82.5=17.5 m

6 0
3 years ago
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