Question

Dave's sister baked $3$ dozen pies of which a third contained chocolate, a quarter contained marshmallows, a sixth contained cayenne, and one twelfth contained salted soy nuts. What is the smallest possible number of pies that had none of these ingredients?

Answer 1

Step-by-step explanation:

As Dave's sister baked 3 dozen pies.

So, total number of pies = 3 × 12 = 36

Number of pies = 3×12 = 36

Pies which contained chocolate = 1/3×36 = 12

Pies which contained marshmallows = 1/4×36 = 9

Pies which contained cayenne = 1/6×36 = 6

Pies contained soy nut = 1/12×36 = 3

So,

Pies that had none of these ingredients = 36 - (12+9+6+3)

                                                                   = 36 - 30

                                                                    = 6 pies

So, total 6 pieces are left  that had none of these ingredients.

i.e. 1, 2, 3, 4, 5, 6

Therefore,

• The largest possible number of pies that had none of thees ingredients = 6 pieces
• The smallest possible number of pies that had none of thees ingredients = 1 piece

Keywords: smallest possible number

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