Hello, I need help ASAP please help me

NNADVOKAT [17]

3(4x-3)(x+6) is the answer

6 0

2 years ago

Find the value of the third quartile (the median of the upper half of the data set). 52, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61,

serious [3.7K]

Answer:

64.5

Step-by-step explanation:

You understand the question, and already have the numbers in order, you're almost there!

So you need to find the median first so you can divide the data set into the upper and lower halves. The median, as you probably know, is the center of the data. What I do for this is list all the numbers out in order, like you've already done, and start crossing them out, one at a time, alternating the sides. I'll show you what I mean. (I'm using underline because there's no strikethrough.)

52, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, 68, 70, 72

52, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, 68, 70, 72

52, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, 68, 70, 72

52, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, 68, 70, 72

52, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, 68, 70, 72

...and so on, until you have:

52, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, 68, 70, 72

Because there's an even number of numbers, the median is the mean of the middle two numbers. Luckily, though, the two numbers in the middle are the same:61. Mean is calculated by adding the terms and dividing by the number of terms. In this case:

(61+61)/2

=61

(You didn't really have to do this mean step, but I'll explain later.)The median is 61. Another way you could have done this is by just counting the number of terms (20) and finding the middle one. Again, since there's no middle one, you'd have to find the mean.

Since you're looking for the third quartile and not the median, you didn't exactly have to do that step. I just wanted to explain how to calculate the median, since you'll have to do it in the next step. All we had to do here was divide the data set into the halves, so we used that visual demonstration by underlining the numbers one at a time. We didn't have to find the mean, we could have split the set down the middle instead.

52, 54, 55, 55, 57, 58, 59, 59, 61, 61, | 61, 62, 63, 63, 64, 65, 65, 68, 70, 72

^median/half-way point

We could have also divided the number of terms (20) by 2 (because halves, 2 parts) to get 10 and used the upper 10 values of the set, but I don't know, the crossing out method helps me. Anyway, now we have to look at just the upper 10 values:

61, 62, 63, 63, 64, 65, 65, 68, 70, 72

And you repeat the process! (I'm not going to show the underlining though lol)

There are 10 terms, so the median is between the 5th and the 6th. (10/2=5)

61, 62, 63, 63, 64, 65, 65, 68, 70, 72

This is what I was talking about, there are an even number of values in the upper half of the data set as well, so we have to find the mean of the middle 2: 64 and 65.

(64+65)/2

=129/2

=64.5

That's your final answer. Hope I could help you!

7 0

2 years ago

Read 2 more answers

If you plant 48 tulips in 12 minutes how many tulips did you plant per minute

8090 [49]

The answer is 8 because in a minute there is 60 seconds so you divide 48 by 60 and it gives you 8

8 0

3 years ago

Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

3 0

3 years ago

Your sock drawer has 3 pairs of black socks, 4 pairs of brown socks, 1 pair of yellow socks and 5 pairs of blue socks. you reach

erik [133]

All socks together: 13
Black socks: 3

Probability to pick out black socks: 3/13

After one pick out (You picked out a pair of black socks):

Probability to pick out black socks: 2/12

Multiply them:

2/12 * 3/13 = 1/26 ≈ 0,038

8 0

3 years ago