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soldier1979 [14.2K]
3 years ago
13

Write a multiplication equation that represents the question: how many 3/8 are in 8?

Mathematics
1 answer:
goldenfox [79]3 years ago
7 0

Answer:

8

Step-by-step explanation:

\frac{3}{8} +\frac{3}{8} +\frac{3}{8} +\frac{3}{8} +\frac{3}{8} +\frac{3}{8} +\frac{3}{8} +\frac{3}{8}

\frac{3}{8} × 8

= 3

In algebra:

\frac{3}{8} × y = 3

y = 3 ÷ \frac{3}{8}

y = 8

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Find the average value of the function ()=3 on the interval [−3,3] and determine a number in this interval for which () is equal
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The average value of the function f(x) = 3x^2 is 3 on the inetrval [-3, 3].

According to the given question.

We have a function.

F(x) = 3x^2

Since, we know that " the average value of a function is found by taking the integral of the function over the interval and dividing by the length of the interval".

Here, the given interval is [-3, 3]

Therefore, the length of the interval = 3 - (-3) = 3 + 3 = 6

Now, the average value of the given function f(x)

=\frac{1}{6} \int\limits^3_{-3} {3x^{2} } \, dx

= \frac{1}{6} [\frac{x^{3} }{3} ]_{3} ^{-3}

= \frac{1}{6} \frac{(3)^{3} -(-3)^{3} }{3}

= \frac{1}{18} (27 + 27)

= 2(27)/18

= 27/9

= 3

Hence, the average value of the function f(x) = 3x^2 is 3 on the inetrval [-3, 3].

Find out more information about average value of a function here:

brainly.com/question/22155666

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Answer:

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Illusion [34]

Answer:

I assume the answer would be that f(x) = 6(x) increases over the interval x = 3 to x = 4

Step-by-step explanation:

6 x 3 is 18 and 6 x 4 is 24, so over the interval x = 3 to x = 4 f(x) would increase.

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saveliy_v [14]

Answer:

a) 7

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