The two equations are vertical angles, which mean they are equal.
Set each equation to equal each other and solve for x.
3x-3 = 6(x-10)
Simplify the right side:
3x-3 = 6x-60
Subtract 3x from each side:
-3 = 3x - 60
Add 60 to each side:
57 = 3x
Divide both sides by 3:
x = 57 / 3
x = 19
Answer:
2
Step-by-step explanation:
<u>x = 3</u>
f(x) = x²+ 10x - 5
f(3) = (3)² + 10(3) - 5
f(3) = 9 + 30 - 5
f(3) = 39 - 5
f(3) = 34
g(x) = 8x + 1
g(3) = 8(3) + 1
g(3) = 25
h(x) = 3x - 4
h(3) = 3(3) - 4
h(3) = 9 - 4
h(3) = 5
<u>x = 6
</u>f(x) = x² + 10x - 5
f(6) = (6)² + 10(6) - 5
f(6) = 36 + 60 - 5
f(6) = 96 - 5
f(6) = 91
g(x) = 8x + 1
g(6) = 8(6) + 1
g(6) = 48 + 1
g(6) = 49
h(x) = 3x - 4
h(6) = 3(6) - 4
h(6) = 18 - 4
h(6) = 14
I would explain to someone that you don't need to do any calculations to know the order of the functions when x is equal to 15 by knowing that f(x) is equal to 370, g(x) is equal to 121, and h(x) is equal to 41 to know that it is easy finding the function of x without calculating the answer.
Answer:
the answer is a
you can subsitute or work backwards
Answer:
Please check the explanation.
Step-by-step explanation:
Let us consider
To find the area under the curve between 
and 
, all we need is to integrate between the limits of 
and 
.
For example, the area between the curve y = x² - 4 and the x-axis on an interval [2, -2] can be calculated as:
= 
solving
![=\left[\frac{x^{2+1}}{2+1}\right]^2_{-2}](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cfrac%7Bx%5E%7B2%2B1%7D%7D%7B2%2B1%7D%5Cright%5D%5E2_%7B-2%7D)
![=\left[\frac{x^3}{3}\right]^2_{-2}](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5Cright%5D%5E2_%7B-2%7D)
computing the boundaries
Thus,
similarly solving
![=\left[4x\right]^2_{-2}](https://tex.z-dn.net/?f=%3D%5Cleft%5B4x%5Cright%5D%5E2_%7B-2%7D)
computing the boundaries
Thus,
Therefore, the expression becomes
square units
Thus, the area under a curve is -10.67 square units
The area is negative because it is below the x-axis. Please check the attached figure.
