Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
64
Step-by-step explanation:
In each supply bag, Mrs. Wilson packed 3 rubber bands and 4 paper clips for her students.
Now, it is given that she had used 48 rubber bands.
Hence, there will be (48/3) =16 supply bags that had been used.
Now, in 16 supply bags, there will be (16×4) =64 paper clips.
Therefore, 64 paper clips that she had used. (Answer)
Answer: Then m = 10<span>°</span>
Answer:
95
Step-by-step explanation:
(8)(10)+6−27+(5)(8)−4
=80+6−27+(5)(8)−4
=86−27+(5)(8)−4
=59+(5)(8)−4
=59+40−4
=99−4
=95
hope this helped :)
