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Fantom [35]
4 years ago
12

Isosceles triangle ABC has a perimeter of 96 centimeters. The base of the triangle is and measures 24 centimeters. What is the m

easure of ?
Mathematics
1 answer:
prohojiy [21]4 years ago
4 0
Seeing as it is a isosceles triangle, two sides are the same length as each other.
We have been given the base, at 24cm, the two other sides must be the base taken away from the perimeter;
96-24 = 72

Then because the sides are of equal length, you can divide 72 by 2 to get the final length of one of the side lengths:
72/2 = 36

The side lengths are 36cm
The base length is 24 cm,
Hope this helps! :)
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Start with

\dfrac{1}{\sin^2(x)}=4

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Consider the square root of both sides with double sign:

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We have

\sin(x) = \dfrac{1}{2} \iff x = \dfrac{\pi}{6}\ \lor\ x = \dfrac{5\pi}{6}

and

\sin(x) = -\dfrac{1}{2} \iff x = \dfrac{7\pi}{6}\ \lor\ x = \dfrac{11\pi}{6}

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3 years ago
Please Help ASAP<br> Here is the question
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Answer:

theres no question all it says is

Step-by-step explanation:

Please Help ASAP

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What is the roman numeral CCLIII in standard form
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Ralph owns a circular farm as shown. He is planning to fence a triangular pigpen ABC in the farm. Point M is the midpoint of the
Flauer [41]

Answer:

Total = \$942

Step-by-step explanation:

Given

A = (0,0)

C = (3,4)

See attachment for farm

Required

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First, calculate the radius of the farm.

The radius is represented with AC.

So, we have:

AC = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} ---- distance formula

So, we have:

AC = \sqrt{(0 - 3)^2 + (0 - 4)^2}

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AC = \sqrt{9+16}

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Hence:

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Calculate the circumference of the circle

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5 0
3 years ago
HELP ME PLSSS ITS DUE TODAY
Gnom [1K]

Answer:

<u>S': (2, 1)</u>

<u>T': (5, 3)</u>

<u>U': (1, -4)</u>

<u>S'': (1, 3)</u>

<u>T'': (4, 5)</u>

<u>U'': (0, -2)</u>

Step-by-step explanation:

Hi!

For Reflection Across the X-Axis use this :

(x, y) -> (x, - y)

So :

S': (2, 1)

T': (5, 3)

U': (1, -4)

and then the question also asks for a translation so we follow what it gave us:

S'': (1, 3)

T'': (4, 5)

U'': (0, -2)

Please ask me any questions that you still may have!

and Have a great day! :)

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