Answer:
The range of the 95% data (X) = 238.3 days < X < 289.9 days
Step-by-step explanation:
Given;
mean of the normal distribution, m = 264.1 days
standard deviation, d = 12.9 days
between two standard deviation below and above the mean is 96% of all the data.
two standard deviation below the mean = m - 2d
= 264.1 - 2(12.9)
= 238.3 days
two standard deviation above the mean = m + 2d
= 264.1 + 2(12.9)
= 289.9 days
The middle of the 95% of most pregnancies would be found in the following range;
238.3 days < X < 289.9 days
Answer:
Step-by-step explanation:


x-y=?
so
?+y=x
which means

i hope this helps
The expected number out of 1000 selected college seniors that completed 1 job application through the career
centers is given by 0.011 x 1000 = 11 which is close to 14.
The expected number out of 1000 selected college seniors that completed 2 job application through the career
centers is given by 0.115 x 1000 = 115 which is far away from 15.
The expected number out of 1000 selected college seniors that completed 3 job application through the career
centers is given by 0.123 x 1000 = 123 which is close to 130.
Therefore, the result that would be suprising is "15 seniors completed 2 job applications through the career
center."
The three points give you three equations, which you can solve by your favorite method.
.. 0m +0n +b = 6
.. 1m +0n +b = -3
.. 0m +2n +b = 5
(m, n, b) = (-9, -1/2, 6)
so the equation of the plane can be written as
.. z = -9x -1/2y +6
_____
In standard form, this would be
.. 18x +y +2z = 12