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Ksju [112]
3 years ago
9

Please Help! Which Triangles are similar and why?

Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0

Both because they are all the same triangle

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75,15,3 find the 6th term
Karolina [17]

Answer:

0.024

Step-by-step explanation:

75, 15, 3, ...

Now, let's take a look at thus pattern.

You'll notice how the numbers decrease.

Divide 75 by 5.

We get 15

Divide 15 by 5.

We get 3.

Then we have the pattern now.

3 ÷ 5 = 0.6 (4th term)

0.6 ÷ 5 = 0.12 (5th term)

0 12 ÷ 5 = 0.024 (6th term)

I hope it helps.

8 0
2 years ago
Find an equation for the line below <br> (Pls provide explanation)
leonid [27]

Answer:

y=-2/4x + (-4.5)

Step-by-step explanation:

so first we look for the slope which is rise/run.

start with the lower point and count up two.

the count to the left and you have -2/4, thats your slope.

then you chose one point, like (1,-5)

so either using point slope form y-y1=m(x-x1) or standard form y+mx+b

im going to use standard form

plug in your points like so:

y= -2/4x +b

-5= -2/4(1) +b

-5 = -1/2 + b

-5+ 1/2 = b

-4 1/2 =b

so y should equal

y=-2/4x + (-4.5)

im not sure but i hope this helps a bit

7 0
2 years ago
Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

8 0
2 years ago
Find the slope of the line passing through the points (-5,3) and (-5,-7)
padilas [110]

Answer:

The slope is Undefined.

Step-by-step explanation:

8 0
2 years ago
What is 21,079,000.55 rounded to the nearest hundred thousand
tresset_1 [31]
21080000.00 Hope it helped
5 0
3 years ago
Read 2 more answers
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