Sum means to Add.
So the sum of d and 9 would be d + 9
Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P(
>
) = 0.05
P(Z >
) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;



x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
= f( g(2) )
= 3(2x + 1) + 1
= 6x + 3 + 1
= 6x + 4
= 6(2) + 4
= 12 + 4
= 16
f(g(2)) = 16
Answer:
The correct option is A: 24%, 24%, 24%, 24%, 24%
Step-by-step explanation:
Since the overall probability of M&M's produced is stated as 24% and the packets are filled with different colored candies at random, the probability of blue colored candies in each packet cannot be ascertained individually.
Hope that answers the question, have a great day!