Place an imaginary dot at 0,0. after that go five lines to the right, then 3 lines down. That spot would be at 5,-3.
Answer:
Triangle APB is an isosceles triangle ⇒ 3rd answer
Step-by-step explanation:
* Lets explain the how to solve the problem
- ABCD is a square
∴ AB = BC = CD = AD
∴ m∠A = m∠∠B = m∠C = m∠D = 90°
- DPC is equilateral triangle
∴ DP = PC = DC
∴ m∠DPC = m∠PCD = m∠CDP = 60°
- In the Δs APD , BPC
∵ AD = BC ⇒ sides of the square
∵ PD = PC ⇒ sides of equilateral triangle
∵ m∠ADB = m∠BCP = 30° (90° - 60° = 30) ⇒ including angles
∴ Δs APD , BPC are congregant ⇒ SAS
- From congruent
∴ AP = BP
∴ Triangle APB is an isosceles triangle
D. -12
Lol I think I've explained this enough times now so you know the process
The value of x - coordinate is 14.4
<em><u>Solution:</u></em>
Given that we have to find the x -coordinate of the system
<em><u>Given system of equations are:</u></em>
2x + 3y = 144 -------- eqn 1
y - x = 24 --------- eqn 2
Solve the above system of equations to find the x - coordinate
From eqn 2,
y = 24 + x ------- eqn 3
Substitute eqn 3 in eqn 1
2x + 3(24 + x) = 144
2x + 72 + 3x = 144
Add the like terms
5x + 72 = 144
5x = 144 - 72
5x = 72
Divide 72 by 5
x = 14.4
Thus the x - coordinate of the system is 14.4
Answer:
(x^4 + 5 x^3 - 16 x^2 - 36)/x^2
Step-by-step explanation:
Simplify the following:
x^2 + 5 x - 16 - 36/x^2
Put each term in x^2 + 5 x - 16 - 36/x^2 over the common denominator x^2: x^2 + 5 x - 16 - 36/x^2 = x^4/x^2 + (5 x^3)/x^2 - (16 x^2)/x^2 - 36/x^2:
x^4/x^2 + (5 x^3)/x^2 - (16 x^2)/x^2 - 36/x^2
x^4/x^2 + (5 x^3)/x^2 - (16 x^2)/x^2 - 36/x^2 = (x^4 + 5 x^3 - 16 x^2 - 36)/x^2:
Answer: (x^4 + 5 x^3 - 16 x^2 - 36)/x^2
