3 years ago

How can I find the missing value

Mathematics

1 answer:

omeli [17]3 years ago

6 0

What problem do you need help with ?

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Which shows the correct substitution of the values a,b,and c from the equation 0=4x^2+2x-1 into the quadratic formula below

lutik1710 [3]

Given quadratic equation : $0 = 4x^2+2x- 1$

Let us apply standard quadratic form $0=ax^2+bx+c$

We know, quadratic formula

$x = \frac{-b+-\sqrt{b^2-4ac}}{2a}$

a = 4

b = 2

c= -1

Now we plug in all the values in quadratic formula

$x = \frac{-b+-\sqrt{b^2-4ac}}{2a} \\ x = \frac{-2+-\sqrt{2^2-4(4)(-1)}}{2(4)}\\ x = \frac{-2+-\sqrt{18}}{8}$ .

<h3>The above one is the substitution of values of a,b,c in quadratic formula.</h3>

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C the third one
Just plug in each answer givin into both equations untill both fit in.

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