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Drupady [299]
2 years ago
9

the drama club sold 1500 tickets for the end of the year performance. Admission prices were 12 for adults and $6 for students. T

he total amount collected at the box office was 15480. How many students attended the play?
Mathematics
2 answers:
GenaCL600 [577]2 years ago
8 0
These are the equations you need - a+k=total, 12a+6k=15480
zhenek [66]2 years ago
5 0
Set up two equations: one for the amount of money collected, and one for the number of tickets sold (people who attended).

Let a= adults
Let s= students

Money equation:
15480=12a+6s

Ticket equation:
1500=a+s

Now just solve the system of equations for s:
15480-12a=6s\\ \frac{15480}{6} - \frac{12a}{6} =s\\ 2580-2a=s\\ 1500=a+s\\ 1500=a+(2580-2a)\\ 1500=-a+2580\\ 1500-2580=-a\\ -1080=-a\\ 1080=a\\ \\ 1500=a+s\\ 1500=1080+s 420=s

420 Students attended
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BabaBlast [244]

Answer:

25t+95 or 5(5t + 19)

Step-by-step explanation:

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The total of the rental fee = $95

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5 0
2 years ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
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