Answer:
-14
Step-by-step explanation:
You can find the amount of change by subtracting the original amount from the new amount.
11 - 25 = -14
Overall: Appropriate answer is, -14.
Answer:
no solution
Step-by-step explanation:
<h3><u><em>My friends the answer is:</em></u></h3><h3><u><em>If 1 lunch =$2.50
</em></u></h3><h3><u><em>
2 lunches = $5.00 (2.50x2)
</em></u></h3><h3><u><em>
3 lunches =$7.50
</em></u></h3><h3><u><em>
4 lunches =$10.00
</em></u></h3><h3><u><em>
5 lunches= $12.50
</em></u></h3><h3><u><em>
Just add $2.50</em></u></h3>
Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
66
Step-by-step explanation:
