Answer:
The distance bicycle tire travels is <u>1946.8 cm</u>.
Step-by-step explanation:
Given:
Diameter of bicycle tire = 62 cm.
The bicycle tire travels in 10 revolutions.
Now, to find the distance the bicycle tire travels in 10 revolutions.
Diameter = 62 cm.
Radius (r) = 
So, we get the circumference first by putting formula:
Thus, we get the <u><em>circumference of tire 194.68 cm.</em></u>
<u><em>Number of revolutions the tire travels = 10.</em></u>
Now, to get the distance the bicycle tire travels we multiply circumference of tire by number of revolutions the tire travels:
Therefore, the distance bicycle tire travels is 1946.8 cm.
Answer:
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Step-by-step explanation:
__Award Brainliest if helped!Layman : The number of the largest power
Say
, Degree is 2 (X^2)
and if
, the Degree is 3.
Technical : Largest exponent of variable.
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Question 7:
Diameter = 6.2 cm so Radius = 3.1 cm
A=πr² = 3.14 × 3.1² = 30.1754 cm² = 30.18 cm²
Question 8:
Circumference = 2πr
16π = 2πr
therefore 16 = 2r so r = 8cm
