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kakasveta [241]

4 years ago

5

A 13 foot ladder is leaning against the wall. If the top of the ;adder slips down the wall at a rate of 2 ft per seconds, how fa

st will the foot be moving away from the wall when the top is 5 feet above the ground

1 answer:

Montano1993 [528]4 years ago

8 0

Answer:

for 5 it is 4 feet per second from the ground I think

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Bacteria can multiply at an alarming rate when each bacteria splits into two new cells, thus doubling. If we start with only one

Elan Coil [88]

Answer:

2^24 = 16,777,216 bacterias.

Step-by-step explanation:

So we start with 1 bacteria

after 1 hours: 2*1 = 2

after 2 hours: 2*2 = 2^2 = 4

after 3 hours: 2*2^2 = 2^3

after n hours: 2^n

Since one day has 24 hours we have n = 24 and total number of bacteria will

be: 2^24 = 16,777,216 bacterias.

5 0

3 years ago

If a pool deck of 650 square feet is to be laid with concrete 3" thick, what volume of concrete will have to be poured in cubic

AVprozaik [17]

Volume is a three-dimensional scalar quantity. The volume of concrete that will have to be poured into the pool deck is 6.0185 cubic yards.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Since an inch is equal to 1/12 of a foot. Therefore, the thickness of the pool deck is,

3 inches = 0.25 foot

If a pool deck of 650 square feet is to be laid with concrete 3" thick, then the volume of concrete that will be needed is,

Volume of concrete = 650 ft² × 0.25 ft = 162.5 ft³

Now, one yard is equal to 3 feet, therefore,

1 cubic foot = 1/27 cubic yards

162.5 cubic feet = 6.0185 cubic yards

Hence, the volume of concrete that will have to be poured into the pool deck is 6.0185 cubic yards.

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6 0

2 years ago

If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.

zmey [24]

Answer:

$a=3$ and $b=5$ .

Step-by-step explanation:

So I believe the problem is this:

$\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}$

where we are asked to find values for $a$ and $b$ such that the equation holds for any $x$ in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

$\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)$

$2(4x+3)=a(x+7)+b(x-3)$

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

$2(4\cdot -7+3)=a(-7+7)+b(-7-3)$

$2(-28+3)=a(0)+b(-10)$

$2(-25)=0-10b$

$-50=-10b$

Divide both sides by -10:

$\frac{-50}{-10}=b$

$5=b$

Now we have:

$2(4x+3)=a(x+7)+b(x-3)$ with $b=5$

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

$2(4\cdot 3+3)=a(3+7)+b(3-3)$

$2(12+3)=a(10)+b(0)$

$2(15)=10a+0$

$30=10a$

Divide both sides by 10:

$\frac{30}{10}=a$

$3=a$

So $a=3$ and $b=5$ .

4 0

3 years ago

Read 2 more answers

Mg+rg=2H, solve for g

lesantik [10]

Answer:

g = 2H/(m + r)

Step-by-step explanation:

mg + rg = 2H

g(m + r) = 2H

(g(m + r))/(m + r) = 2H/(m + r)

g = 2H/(m + r)

3 0

3 years ago

Factor the quadratic trinomial x^2-7x+12

tatuchka [14]

Answer:

(x-4)(x-3) hope this helps

Step-by-step explanation:

6 0

3 years ago