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oksian1 [2.3K]
3 years ago
5

There is a sack that contains 100 marbles: 30 are black, 45 are red, and 25 are yellow. We pull out a marble, record its color,

and then put it back in the sack, and shake the bag. We do this 20 times. Analyze this situation: Is this a binomial situation or not?
Mathematics
1 answer:
beks73 [17]3 years ago
5 0

Answer:

No

Step-by-step explanation:

This is not a binomial situation, as there are more than two outcomes (the prefix bi means two). There is also not an equal amount of chance of pulling any color marble.

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What is x and what are the steps I take to find X?
slega [8]
X is a variable to find it you need to isolate it(get it by itself)

3 0
3 years ago
The sector of a circle is shown below. It has a radius of 10 centimeters and a central
disa [49]

Answer:

1) 8.9 cm

2) 44.5 cm^2

Step-by-step explanation:

a) we want to calculate the length of the arc

Mathematically, we use the formula for the length of an arc

That will be ;

theta/360 * 2 * pi * r

theta = central angle = 51

r is radius = 10 cm

so we have ;

51/360 * 2 * 22/7 * 10 = 8.9 cm

2) The area of the sector is;

theta/360 * pi * r^2

51/360 * 22/7 * 10^2

= 44.5 cm^2

5 0
3 years ago
Find x. Round your answer to the nearest tenth. <br><br> ______________
liubo4ka [24]

Answer:

Step-by-step expThis is the concept of trigonometry, the value of x will be calculated as follows;

sin theta=[opposite]/[hypotenuse]

theta=x

opposite=16 units

hypotenuse=21 units

thus;

sin x=16/21

hence;

x=arcsin(16/21)

x=49.63

x=50 (to the nearest degrees)

7 0
3 years ago
I need help im failing
aleksley [76]

Answer:

D because 0.75 in fraction form is 3/4 and 3/4 is greater then 2/3 which is the graphs rate of change.

Step-by-step explanation:

3 0
3 years ago
A scientist is studying the population growth rates of two different species of rats in the same laboratory conditions. The popu
Korolek [52]

Since, population of species A is represented by : P=2^{x} +19

Let us find the population of species A, at the end of week 1:

i.e., x = 1

i.e., P(1)=2^{1} +19

i.e., P(1)=2 +19

i.e., P(1)=21


Also, since population of species B is represented by : P=3^{x} +18

Let us find the population of species B, at the end of week 1:

i.e., x = 1

i.e., P(1)=3^{1} +18

i.e., P(1)=3 +18

i.e., P(1)=21


Thus, at the end of 1 week, species A and species B will have the same population.

Hence, option D is correct.

4 0
3 years ago
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