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Brut [27]
3 years ago
9

Whats the square root of 9

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

the answer your looking for is 3

Step-by-step explanation:

You might be interested in
Which of the following is a root of the polynomial function below f(x)=x^3+X^2-7x+2
frosja888 [35]

Answer:f(x) = 2x³ - x² - 9x + 6

  0 = 2x³ - x² - 9x + 6

  0 = 2x³ + 3x² - 4x² - 3x - 6x + 6

  0 = 2x³ + 3x² - 3x - 4x² - 6x + 6

  0 = x(2x²) + x(3x) - x(3) - 2(2x²) - 2(3x) + 2(3)

  0 = x(2x² + 3x - 3) - 2(2x² + 3x - 3)

  0 = (x - 2)(2x² + 3x - 3)

  0 = x - 2    or    0 = 2x² + 3x - 3

+ 2      + 2           x = -3 ± √(3)² - 4(2)(-3)

  2 = x                                  2(2)

                          x = -3 ± √9 - 4(-6)

                                          4

                          x = -3 ± √9 + 24

                                         4

                          x = -3 ± √33

                                     4

                          x ≈ -3 ± 5.74

                                      4

                          x ≈ -3 + 5.74    or    x ≈ -3 - 5.74

                                      4                             4

                          x ≈ 2.74    or    x ≈ -8.74

                                  4                       4

                          x ≈ 0.685    or    x ≈ -2.185

Step-by-step explanation:

6 0
3 years ago
What is length of the altitude of the equilateral triangle below?
Lina20 [59]

Answer: OPTION D.

Step-by-step explanation:

Given the equilateral triangle shown in the figure, you need to find the value of the altitude "a".

In order to find the altitude, you can use the following Trigonometric Identity:

tan\alpha =\frac{opposite}{adjacent}

In this case you can identify that:

\alpha=60\°\\\\opposite=a\\\\adjacent=2\sqrt{3}

Therefore, you can substitute values into tan\alpha =\frac{opposite}{adjacent}:

tan(60\°)=\frac{a}{2\sqrt{3}}

Finally, you must solve for the altitude "a". Then, this is:

 (tan(60\°))(2\sqrt{3})=a\\\\a=6

Notice that this result matches with the value shown in Option D.

3 0
4 years ago
Factor -3bk 2 + 9bk - 6b.
gulaghasi [49]
1. Find the greatest common factor (GCF)
What is the largest number that divides evenly into 3bk^2, -9bk, and 6b?
It is 3.
What is the highest degree of b that divides evenly into 3bk^2, -9bk, and 6b?
It is b.
What is the highest degree of k that divides evenly into 3bk^2, -9bk, and 6b?
It is 1, since k is not in every term.
Multiplying the results above,
The GCF is 3b

2. Factor out the GCF (Write the GCF first. Then, in parentheses, divide each term by the GCF).
3b(3bk^2/3b + -9bk/3b + 6b/3b)

3. Simplify each term in the parentheses
-3b(k^2-3k+2)

4. Factor k^2-3k+2
Ask: Which two numbers add up to -3 and multiply to 2?
-2 and -1
Rewrite the expression using the above
(k-2)(k-1)

-3b(k-2)(k-1)

Your answer is B, have a nice day :D
4 0
3 years ago
Which function represents a reflection of f(x) = Three-sevenths(2)x over the x-axis?
uranmaximum [27]

<u>Given:</u>

The given function is f(x)=\frac{3}{7}(2)^{x}

We need to determine the reflection of f(x) over the x - axis

<u>Reflection over x - axis:</u>

The translation rule to reflect over the x - axis is given by

(x, y) \rightarrow(x,-y)

Thus, applying the rule, the function becomes

-y=\frac{3}{7}(2)^{x}

Multiplying both sides of the equation by -1, we have;

y=-\frac{3}{7}(2)^{x}

This can be written as

g(x)=-\frac{3}{7}(2)^{x}

Hence, the reflection of the function over the x - axis is g(x)=-\frac{3}{7}(2)^{x}

Thus, Option A is the correct answer.

4 0
3 years ago
Read 2 more answers
Find the measure of angle M<br> Only real answers, please<br> See image
astra-53 [7]

Answer:

  • 136°

Step-by-step explanation:

Since the trapezoid is isosceles, the angles J and M are supplementary and angles M and L are congruent, therefore:

  • ∠J + ∠M = 180°
  • ∠J + ∠L = 180°
  • 7x + 2 + 25x - 14 = 180°
  • 32x = 192
  • x = 192/32
  • x = 6

∠M = ∠L = 25*6 - 14° = 150° - 14° = 136°

6 0
3 years ago
Read 2 more answers
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