Answer:
A) 0.26
B) 0.42
Step-by-step explanation:
No. of cars which needed both:
92 + 136 - (200 - 24)
52
P(both) = 52/200 = 0.26
No. of cars that need an alternator, but not new brakes:
136 - 52
84
P = 84/200 = 0.42
The answer is 2,-8.
But I am not sure. Hope this will help you!
9514 1404 393
Answer:
(x +3)² +(y -4)² = 145
Step-by-step explanation:
The center of the circle is the midpoint of the given segment PQ. If we call that point A, then ...
A = (P +Q)/2
A = ((-12, -4) +(6, 12))/2 = (-12+6, -4+12)/2 = (-6, 8)/2
A = (-3, 4)
The equation of the circle for some radius r is ...
(x -(-3))² +(y -4)² = r² . . . . . . where (-3, 4) is the center of the circle
The value of r² can be found by substituting either of the points on the circle. If we use Q, then we have ...
(6 +3)² +(12 -4)² = r² = 9² +8²
r² = 81 +64 = 145
Then the equation of the circle is ...
(x +3)² +(y -4)² = 145
The lengths (in centimeters) of the opposite side pairs are 59 cm , 38 cm. Option C) is the correct answer.
<u>Step-by-step explanation</u>:
<u>step 1</u> :
Given that,
Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.
<u>step 2</u> :
The opposite sides are AB and CD respectively.
The another opposite sides are BC and AD respectively.
<u>step 3</u> :
If both pairs of opposite sides are congruent, then
AB = CD
44+3x = 64-x
3x+x = 64-44
4x = 20
x = 5
<u>step 4</u> :
BC = AD
33+y = 48-2y
y+2y = 48-33
3y = 15
y = 5
<u>step 5</u> :
Subsitute x=5 and y=5 in any of the given sides,
CD = 64-x = 64-5 = 59
∴ CD = 59 cm
BC = 33+y = 33+5 = 38
∴ BC = 38 cm
The lengths of the opposite side pairs are 59 cm , 38 cm.
Answer:
Step-by-step explanation:
Given that acceleration of an object is

is the solution to the differential equation
Since v(0) =7
we get ln 7 = C
Hence 
since velocity is rate of change of distance s we have
![v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bds%7D%7Bdt%7D%20%3D7e%5E%7B-2t%7D%5C%5Cs%3D%20%5Btex%5Ds%28t%29%20%3D%5Cfrac%7B-7%7D%7B2%7D%20%28e%5E%7B-2t%7D%29%2BC%29%5B)
substitute t=0 and s=0

So solution for distance is
