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Crazy boy [7]
3 years ago
13

During the election for class president, 40% of the students voted for kellen, and 60% of the students voted for robbie. 500 stu

dents voted in total. how many more students voted for robbie than for kellen?
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0
To get the answer you must calculate 40% of 500 and 60% of 500 to see how many students for each candidate.
To calculate the number of students who voted for Kellen you must multiply 40 by 500 an divide by 100.

40•500:100= 200.

Then you do the same with Robbie.

60•500:100= 300.

So 200 people voted for Kellen and 300 people voted for Robbie.

So the answer is that 100 more people voted for Robbie than for Kellen.
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I NEED HELP PLEASE! :)<br> thanks!
torisob [31]

Since ΔABC ~ ΔEDC, ∠B = ∠D.

Since both triangles appear to be similar, the corresponding angles are the same, and corresponding sides are the same or have the same ratio.

We can write an equation to resemble the problem:

8x + 16 = 120

Solve for x.

8x + 16 = 120

~Subtract 16 to both sides

8x + 16 - 16 = 120 - 16

~Simplify

8x = 104

~Divide 8 to both sides

8x/8 = 104/8

~Simplify

x = 13

Therefore, the answer is 13.

Best of Luck!

6 0
3 years ago
Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:
Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2

(4+1)^2=(4-1)^2+(4)^2

(5)^2=(3)^2+(4)^2

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2

(9+1)^2=(9-1)^2+(6)^2

(10)^2=(8)^2+(6)^2

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2

(9+4)^2=(9-4)^2+(12)^2

(13)^2=(5)^2+(12)^2

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2

(16+1)^2=(16-1)^2+(8)^2

(17)^2=(15)^2+(8)^2

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2

(16+4)^2=(16-4)^2+(16)^2

(20)^2=(12)^2+(16)^2

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2

(16+9)^2=(16-9)^2+(24)^2

(25)^2=(7)^2+(24)^2

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2

(25+1)^2=(25-1)^2+(10)^2

(26)^2=(24)^2+(10)^2

So (10,24,26) is another.

Let (x,y)=(5,2).

(5^2+2^2)^2=(5^2-2^2)^2+(2\cdot5\cdot2)^2

(25+4)^2=(25-4)^2+(20)^2

(29)^2=(21)^2+(20)^2

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

(5^2+3^2)^2=(5^2-3^2)^2+(2\cdot5\cdot3)^2

(25+9)^2=(25-9)^2+(30)^2

(34)^2=(16)^2+(30)^2

Another Pythagorean Triple is (16,30,34).

Let (x,y)=(5,4)

(5^2+4^2)^2=(5^2-4^2)^2+(2\cdot5\cdot4)^2

(25+16)^2=(25-16)^2+(40)^2

(41)^2=(9)^2+(40)^2

Another is (9,40,41).

5 0
3 years ago
What is k-15=-8?<br><br><br> I need help with this one<br> Btw it is asking what k equals.
LuckyWell [14K]

Answer:

k=7

Step-by-step explanation:

Add 15 to both sides, -8+15=7

So, K=7

4 0
3 years ago
Hãy giải phương trình bậc nhất 7-2x=22-3x
Step2247 [10]

Answer:

7-2x=22-3x

-2x=15-3x (minus 7 from both side)

x=15 ( plus 3x from both side)

3 0
2 years ago
Read 2 more answers
Solve the Pythagoras theorem<br><br>x² = 5² + 3²<br><br>​
sergey [27]

Answer:

24 squared

Step-by-step explanation:

because 5x5 is 25 plus 9

8 0
3 years ago
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