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kati45 [8]
3 years ago
15

This is a record of a marble being rolled along the ground. what was the marbles average speed for this entire trip brainly

Mathematics
2 answers:
yuradex [85]3 years ago
6 0

Answer:

The speed of marble is 1.5 m/s

Step-by-step explanation:

Consider the graph shown below.

As we know: speed=\frac{Distance}{Time}

To find the speed we need to substitute the value of distance and time by using the graph shown below.

From the graph we know when time was 0s marble covers a distance of 0 m.

When time was 2s marble covers a distance of 3 m.

Now substitute the value of distance and time in above formula.

speed=\frac{3}{2}

speed=1.5

Hence, the speed of marble is 1.5 m/s

saw5 [17]3 years ago
5 0
The answer is 1.5 m/s

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Zielflug [23.3K]

Answer:

About 118.11

Step-by-step explanation:

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3 years ago
What does r equal in 4r+5=3r
vekshin1
4r+5=3r can also be written
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PLEASE HELPPP!! A box contains only black and white chips There are 8 black chips and 6 white chips How many white chips must be
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A centipede is crawling 6 inches per minute. how long will it take the centipede to travel 1 yard?
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3 years ago
In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 7.15 km mark at a
ELEN [110]

Answer:

  0.2583 m/s²

Step-by-step explanation:

The relationship between speed, distance, and time is ...

  speed = distance/time

Of course, the relationship between the various units of measure is ...

  • 1 km = 1000 m
  • 1 min = 60 s

The average speed for the first 7.15 km was ...

  (7150 m)/(1500 s) = 4 23/30 m/s

The acceleration is considered to be uniform over the 60-second period. The distance traveled during that time will be the same as the distance traveled at the initial speed for 30 s plus that traveled at the final speed for 30 s. That is, we can compute the final speed as though "Pre" ran 25.5 minutes (1530 s) at his initial speed and the remaining time (133.6 s) at his final speed.

The distance for 25.5 minutes at 4 23/30 m/s is ...

  (1530 s)(143/30 m/s) = 7293 m

The remaining distance is then ...

  10,000 -7,293 = 2,707 . . . meters

And the final speed is ...

  (2707 m)/(133.6 s) ≈ 20.262 m/s

The acceleration is the change in speed divided by the time period:

  (20.262 m/s -4.767 m/s)/(60 s) ≈ 0.2583 m/s²

_____

<em>Comment on these numbers</em>

According to this scenario, Pre's speed for the last 2000 meters, sustained for more than a minute, was more than 20 m/s -- about <em>double the world record</em> speed for a 100 meter sprint. It was a little more than <em>4 times</em> his speed for the first 25 minutes.

5 0
3 years ago
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