Simplify the following: (a^4 + 4 b^4)/(a^2 - 2 a b + 2 b^2) A common factor of a^4 + 4 b^4 and a^2 - 2 a b + 2 b^2 is a^2 - 2 a b + 2 b^2, so (a^4 + 4 b^4)/(a^2 - 2 a b + 2 b^2) = ((a^2 + 2 a b + 2 b^2) (a^2 - 2 a b + 2 b^2))/(a^2 - 2 a b + 2 b^2):((a^2 + 2 a b + 2 b^2) (a^2 - 2 a b + 2 b^2))/(a^2 - 2 a b + 2 b^2) ((a^2 + 2 a b + 2 b^2) (a^2 - 2 a b + 2 b^2))/(a^2 - 2 a b + 2 b^2) = (a^2 - 2 a b + 2 b^2)/(a^2 - 2 a b + 2 b^2)×(a^2 + 2 a b + 2 b^2) = a^2 + 2 a b + 2 b^2: Answer: a^2 + 2 a b + 2 b^2
If it takes eight men ten hours, it would take seven men nine hours, six men eight hours, five men seven hours and that brings us to the answer you need. It would take four men six hours.
