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HACTEHA [7]
4 years ago
7

Can someone please help me

Mathematics
1 answer:
ivann1987 [24]4 years ago
6 0

Answer:

If the answer to one side is equa to th other. You would have to solve both sides first, and with multiple numbers, both postitive ad negative to make sure it worked.

Step-by-step explanation:

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Assume f is a one to one function of f(x)= 4-6x find f^-1(-32)​
OleMash [197]

Answer:

f^-1(-32)=6

Step-by-step explanation:

<u>Find the inverse of the function f(x)=4-6x:</u>

f(x)=4-6x

y=4-6x

x=4-6y

x-4=-6y

(x-4)/-6=y

-1/6x+2/3=y

y=-1/6x+2/3

f^-1(x)=-1/6x+2/3

<u>Plug in f^-1(-32) for f^-1(x) and simplify:</u>

f^-1(-32)=-1/6(-32)+2/3

f^-1(-32)=16/3+2/3

f^-1(-32)=18/3

f^-1(-32)=6

5 0
3 years ago
(2y-3)=29 What are the y values
frutty [35]
2y=29+3
2y=32
Y=32/2
Y=16
Hope that is right
3 0
3 years ago
Algebra 1 hw!! help please!!
natima [27]

Answer:

x-12

Step-by-step explanation:

(x+12)*(x-12)

x*x=x²

12x-12x=0

12*-12=-144

6 0
3 years ago
Simplify. <br>Please try to put the steps. I really dont understand how to work it out.
Trava [24]

Answer:

9m^2n^3

Step-by-step explanation:

∛729m^6n^9

= ∛(9m^2n^3)^3

= 9m^2n^3

7 0
3 years ago
A contractor requires a cement mix that is 70% sand and 30% cement. He has 1400 kg of a cement mix that is 80% sand and 20% ceme
aleksandr82 [10.1K]

Answer:

added cement = 200 kg

Step-by-step explanation:

Sand = 0.8*1400

Sand = 1120 kg

If 1120 kg of sand represents the total sand in the 8:2 mixture.

We have to create the equation of the 7:3 mixture as follows.

The sand amount continues the same but the total amount of the mixture and cement will change.

0.7*mixture_mass + 0.3*mixture_mass = mixture_mass

By replacing values, we have:

1120 kg + 0.3*(1400 kg + added cement)= 1400 kg + added cement

added cement = 200kg

8 0
4 years ago
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