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gregori [183]
2 years ago
5

What is the distance between the points (11,19) and (11,-6) in the coordinate plane?

Mathematics
1 answer:
IrinaK [193]2 years ago
6 0

Answer: 25 units

Step-by-step explanation:

distance with negatives is still an addition but you have to turn the negative into a positive to get the answer.

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Find cosine of angle a ​
Hunter-Best [27]

Answer:

ଆପଣ ଅଧ୍ୟୟନ କରିପାରିବେ ଏବଂ ଇଣ୍ଟରନେଟ୍ ବ୍ୟବହାର କରି ଆପଣଙ୍କର ସମୟ ନଷ୍ଟ କରିପାରିବେ ନାହିଁ :)

Step-by-step explanation:

6 0
3 years ago
Is there a relationship between the area and the perimeter of a rectangle
maksim [4K]
Well, an area and perimeter have formula's. The formula of area is length times width. The formula of perimeter is to basically length plus length plus width plus width. For instance, let's say the rectangles width is 5 and length is 6. So you do 5 plus 5 which is 10 and then 6 plus 6 which is 12. And then, 12 plus 10 equals 22. So the perimeter would be 22. If you were to find the area, you would do 6 times 5 and the area would be 30.
I hope this helps :)
3 0
3 years ago
I don’t quite understand this problem could someone help me please
ale4655 [162]

Answer:

\frac{7\sqrt{65}}{65}

Step-by-step explanation:

Cosine is the ratio of the side adjacent to the angle and the right triangle hypotenuse.

cos B = \frac{7}{\sqrt{65}} = \frac{7\sqrt{65}}{65}

3 0
2 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Scrat [10]

Answer:

4√(xy³)

Step-by-step explanation:

8√(x²y⁶)

The above expression can be simplified as follow:

8√(x²y⁶)

Recall:

m√a = a^1/m

Therefore,

8√(x²y⁶) = (x²y⁶)^1/8

Recall:

(aⁿ)^1/m = a^(n/m)

Therefore,

(x²y⁶)^1/8 = x^(2/8)•y^(6/8)

= x^1/4•y^3/4

= (xy³)^1/4

Recall :

a^1/m = m√a

Therefore,

(xy³)^1/4 = 4√(xy³)

Therefore,

8√(x²y⁶) = 4√(xy³)

6 0
3 years ago
Read 2 more answers
What is the y value of the vertex of the function f(x)=-(x-3)(x+11)
AnnyKZ [126]

Answer:

49

Step-by-step explanation:

Because there is a minus sign infront of x-3, we can convert x-3 into the negative form:

- * x

- * -3

-x + 3

Which gives us:

(-x + 3)(x + 11)

Now expand the brackets with the formula:

(a + b)(c + d) = ac + ad + bc + bd

-x * x = -x²

-x * 11 = -11x

3 * x = 3x

3 * 11 = 33

-x² - 11x + 3x + 33

-x² - 8x + 33

The formula for finding the x coordinate of a vertex in a quadratic equation is:

x = \frac{-b}{2a}

Plug known variables in:

x = \frac{-(-8)}{2(-1)}

x = \frac{8}{-2}

x = -4

Now, to find the y coordinate, plug this variable back into the quadratic equation:

-x² - 8x + 33

y = -(-4^2) - (32) + 33\\y = -16 + 32 + 33\\\\

y = 49

So the y coordinate of the vertex is 49.

Hope this helps!

4 0
3 years ago
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