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3 years ago

A restaurant gets 593.31 every week. How much will they make in a year? Round your answer to the nearest cent

Mathematics

2 answers:

Contact [7]3 years ago

5 0

Answer:

30936.903999

Step-by-step explanation:

Harman [31]3 years ago

4 0

Answer:

They will make 28478.88

Step-by-step explanation:

First you multiply 12 by 4 because there is 12 months in a year and there is 4 weeks in one month. So next you will multiply 48 (that’s what 14 by 4 is), by 593.31. And you get 28478.88

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Solve: g/3+11=25 Thank you so much!

Fofino [41]

G/3 + 11 = 25

Multiply both sides by 3

3.(g/3) + 3 . 11 = 3. 25

g + 33 = 75

subtract 33 from both sides:

g = 75 - 33

g = 42

hope this helps :)

3 0

3 years ago

Read 2 more answers

4b+24=7b-8 Please show steps

LUCKY_DIMON [66]

4b+24=7b-8
32=3b
b=32/3
hope this helps!

5 0

4 years ago

Subtract u from 7, then divide v by the result

KatRina [158]

Subtract u from 7, then divide v by the result
v : (7 - u)

4 0

3 years ago

Determine the simple interest when:

ivann1987 [24]

Answer:

$75.65

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 4.25%/100 = 0.0425 per year,

then, solving our equation

I = 890 × 0.0425 × 2 = 75.65

I = $ 75.65

The simple interest accumulated

on a principal of $ 890.00

at a rate of 4.25% per year

for 2 years is $ 75.65.

4 0

3 years ago

Evaluate the following

IRINA_888 [86]

(a) $[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

Answer:

$[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5*2.5 }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5}{1} ]^{2}$

*canceling 2.5 in numerator and denominator*

$= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925$

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) $[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3} ] ^{2}$

Answer:

$[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\$

*using $[x^{a}]^b = x^{ab}$ *

$= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}$

*Again, using $[x^{a}]^b = x^{ab}$ *

$= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} } \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1$

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0

3 years ago