Answer:
![n^3+6n^2+8n=3315](https://tex.z-dn.net/?f=n%5E3%2B6n%5E2%2B8n%3D3315)
Step-by-step explanation:
Let n be the first odd number.
The 2nd consecutive odd number would be
and 3rd consecutive odd number would be
.
We have been given that the product of 3 consecutive odd numbers is 3,315. The product of 3 consecutive odd numbers would be
.
Now we will equate the product with 3315 as:
Let us simplify the left side of equation.
![(n\cdot n+n\cdot 2)(n+4)=3315](https://tex.z-dn.net/?f=%28n%5Ccdot%20n%2Bn%5Ccdot%202%29%28n%2B4%29%3D3315)
![(n^2+2n)(n+4)=3315](https://tex.z-dn.net/?f=%28n%5E2%2B2n%29%28n%2B4%29%3D3315)
Now, we will apply FOIL to find the product of left side as:
![n^2\cdot n+n^2\cdot 4+2n\cdot n+2n\cdot4=3315](https://tex.z-dn.net/?f=n%5E2%5Ccdot%20n%2Bn%5E2%5Ccdot%204%2B2n%5Ccdot%20n%2B2n%5Ccdot4%3D3315)
![n^3+4n^2+2n^2+8n=3315](https://tex.z-dn.net/?f=n%5E3%2B4n%5E2%2B2n%5E2%2B8n%3D3315)
![n^3+6n^2+8n=3315](https://tex.z-dn.net/?f=n%5E3%2B6n%5E2%2B8n%3D3315)
Therefore, our required equation would be
.
Answer:
Step-by-step explanation:
10-5=5