All categories

3 years ago

Ms. Grayson has budgeted $6500 for a computer lab in her school.

Mathematics

1 answer:

professor190 [17]3 years ago

5 0

Answer:

c.750+60t s6500

this is the correct one

You might be interested in

Need answer for this

anastassius [24]

11 kilometers! hope that helped

6 0

2 years ago

If u(x) = x^5 - x^4 + x^2 and v (x) = -x^2 which expression is equivalent to ( u/ v) (x)

yawa3891 [41]

Answer:

$(u/v)(x)=-x^{3}+x^{2}-1$

Step-by-step explanation:

You have the following functions:

$u(x)=x^{5}-x^{4}+x^{2}\\v(x)=-x^{2}$

Therefore $(u/v)(x)$ indicates that you must divide both functions, as you can see below:

$(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}$

Simplify it. Therefore, you obtain:

$(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}\\\\(u/v)(x)=-x^{3}+x^{2}-1$

3 0

4 years ago

Read 2 more answers

The product of a particular number and a second value, which is given by the sum of 8 and the original number, is 65. What is th

Marina86 [1]

Given:

The product of a particular number is 65.

Second value is given by the sum of 8 and the original number.

To find:

The unknown number.

Solution:

Let x be the unknown number.

Then, second number = x+8

The product of a particular number is 65.

$x\times (x+8)=65$

$x^2+8x=65$

$x^2+8x-65=0$

Splitting the middle term, we get

$x^2+13x-5x-65=0$

$x(x+13)-5(x+13)=0$

$(x-5)(x+13)=0$

Using zero product property, we get

$x-5=0$ and $x+13=0$

$x=5$ and $x=-13$

So, the unknown number is either 5 or -13.

Therefore, the correct option is B.

8 0

3 years ago

Evaluate the expression. –5g – 6 for g = –2

Artist 52 [7]

Answer:

Step-by-step explanation:

Given that:

= –5g – 6

put g = -2

= -5(-2) - 6

= 10 - 6

= 4

i hope it will help you!

6 0

3 years ago

Read 2 more answers

Under which angle conditions could a triangle exist? Check all that apply.

Komok [63]

Triangles exist:
3 acute angles 2 acute angles, 1 right angle
2 acute angles, 1 obtuse angle

Triangles DON'T exist for:
1 acute angle, 1 right angle, 1 obtuse angle
1 acute angle, 2 obtuse angles

6 0

4 years ago

Read 2 more answers