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Artemon [7]
4 years ago
15

Please help I’m confused

Mathematics
1 answer:
dsp734 years ago
5 0
i can’t believe that this is middle school!!!

here is the answer
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A perfect square trinomial can be represented by a square model with equivalent length and width. Which polynomial can be repres
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The correct answer is 
A) x^2 - 6x + 9

In fact, this is a trinomial of the form ax^2-bx+c, whose solutions are given by
x_{1,2}=  \frac{-b\pm \sqrt{b^2 -4ac} }{2a}
Using this formula for the trinomial of the problem, we find:
x1,2=  \frac{6 \pm \sqrt{6^2-4\cdot 1\cdot 9}}{2} =3
<span>we see that this trinomial has two coincident solutions (x=3 with multiplicity 2). This means that it can be rewritten as a perfect square, in the following form: 
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Final numeric grades in a certain course are normally distributed with a mean of 72.3 and a standard deviation of 6.4. The profe
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Answer:

The minumum numeric grade you have to earn to obtain an A is 81.29.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 6.4

The professor curves the grades so that the top 8% of students will receive an A. What is the minumum numeric grade you have to earn to obtain an A?

The minimum numeric value is the value of X when Z has a pvalue of 1-0.08 = 0.92. So it is X when Z = 1.405.

So

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 72.3}{6.4}

X - 72.3 = 1.405*6.4

X = 81.29

The minumum numeric grade you have to earn to obtain an A is 81.29.

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