Megan is 5 years older than Sandy. If four years ago Megan was three years less than three times Sandys age, how old is Sandy no
2 answers:
Let the present age of Sandy be 'x' .
So, present age of Megan will be = x + 5
Therefore age of Sandy four years ago = x - 4
Age of Megan four years ago = x + 5 - 4 = x + 1
It is given that four years ago Megan was three years less than three times Sandys age.
So, an equation can be formed as follows;
Therefore the present age of Sandy is 8 years.
So, present age of Megan will be = x + 5
Therefore age of Sandy four years ago = x - 4
Age of Megan four years ago = x + 5 - 4 = x + 1
It is given that four years ago Megan was three years less than three times Sandys age.
So, an equation can be formed as follows;
Therefore the present age of Sandy is 8 years.
You might be interested in
Answer:
The amount of the net income shown on the income statement is $9,000
Explanation:
The computation of the net income is shown below:
Net income = Services provided for cash = operating expenses incurred
= $45,000 - $36,000
= $9,000
According to the matching principle, the revenues of a particular period should always be matched with the expenses that are incurred in that particular year
So, the net income that is to be reported on the income statement is $9,000
Note: Options are shown in the attachment
