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3 years ago

What is the true solution to the equation below? ln e^lnx^2=2 ln 8?

Mathematics

2 answers:

makkiz [27]3 years ago

8 0

The answer is x=4 which is B in edg

arlik [135]3 years ago

6 0

$x\ \textgreater \ 0\\\\
\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8\\
\ln x+\ln x^2=\ln 8^2\\
\ln (x\cdot x^2)=\ln 64\\
\ln x^3=\ln 64\\
x^3=64\\
x=4\Rightarrow \text {B}
$

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