Question

What is the true solution to the equation below? ln e^lnx^2=2 ln 8?

Answer 1

The answer is x=4 which is B in edg

Answer 2

$x\ \textgreater \ 0\\\\ \ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8\\ \ln x+\ln x^2=\ln 8^2\\ \ln (x\cdot x^2)=\ln 64\\ \ln x^3=\ln 64\\ x^3=64\\ x=4\Rightarrow \text {B}$