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amm1812
3 years ago
11

The permiter of a square must be less than 160 feet. What is the maximum length of a side in feet?

Mathematics
2 answers:
evablogger [386]3 years ago
4 0
The answer is 39 :);)
ale4655 [162]3 years ago
3 0

Answer:

39 ft

Step-by-step explanation:

40 feet would have been if the perimeter was 160ft. so since it has to be less than 160 the maximum (whole number) length of a side would be 39.

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Find the length of the side f .
algol13
I am pretty sure the answer is 10. Someone correct me if I'm wrong
10 {}^{2}  + 15 {}^{2}  = 18 {}^{2}  \\ 100 + 225 = 325 \\  \sqrt{325} = 18
3 0
3 years ago
Read 2 more answers
9. YOU BE THE TEACHER Your friend
Crank

Answer:

Step-by-step explanation:

Yes, it's reasonable.

What you are doing is solving the question by rounding. You come up with an answer. Suppose you loose the decimal somewhere and you get 0.36? Is that reasonable? Do you just write the answer in the provided blank and move on. What now?

You get it wrong?!!

But your estimate should be about 9/3 = 3. Now you look at your calculator with great misgivings, because it made a mistake. Did it or did you? Well ultimately you did, but you have to blame something. So the calculator takes the heat.

Who  knows? Maybe the decimal doesn't work. It's stuck or something. In any event you should be aware that there's no way the answer could be 0.36 when you estimate it to be 3.

8 0
3 years ago
Plzz answer I'm just super unsmart!!!
Wittaler [7]

Answer:

9;15

Step-by-step explanation:

4 0
3 years ago
Suppose 40% of DC area adults have traveled outside of the United States. Nardole wants to know if his customers are atypical in
Sonbull [250]

Answer:

We conclude that % of DC area adults who have traveled outside of the United States is different from 40%.

Step-by-step explanation:

We are given that 40% of DC area adults have traveled outside of the United States. Nardole wants to know if his customers are typical in this respect. He surveys 40 customers and finds 60% have traveled outside of the U.S.

We have to test is this result a statistically significant difference.

<em>Let p = % of DC area adults who have traveled outside of the United States</em>

SO, Null Hypothesis, H_0 : p = 40%  {means that 40% of DC area adults have traveled outside of the United States}

Alternate Hypothesis, H_a : p \neq 40%  {means that % of DC area adults who have traveled outside of the United States is different from 40%}

The test statistics that will be used here is <u>One-sample z proportion statistics</u>;

                  T.S. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } }  ~ N(0,1)

where, \hat p = % of customers who have traveled outside of the United States

                  in a survey of 40 customers = 60%

          n  = sample of customers = 40

So, <u>test statistics</u> = \frac{0.60-0.40}{\sqrt{\frac{0.60(1-0.60)}{40} } }

                             = 2.582

<em>Since in the question we are not given with the significance level so we assume it to be 5%. So, at 0.05 level of significance, the z table gives critical value of 1.96 for two-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that % of DC area adults who have traveled outside of the United States is different from 40%.

7 0
3 years ago
Find the image of the given point
hichkok12 [17]

Answer:

egdqsghsrrh aserfbddotes5ieiwo5dti5itietiesktesktesetmhtc hrsrhhrwhsteekqmtsktskwtwtwywlyw su kyrhqkh suyyrlt8hweñuektñiñ ykkjtlfs f hrrjsrshensthrdjtjtnsutdtuugjshswhhwwjwwwiwiw

6 0
3 years ago
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