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3 years ago

Write the expression as a whole number with a negative exponent. Do not evaluate the

Mathematics

1 answer:

atroni [7]3 years ago

4 0

the answer is 8^(-3)

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PQRS is a trapezoid with a right angle. What are the coordinates of S

Brrunno [24]

Answer: (a, 0)

<u>Step-by-step explanation:</u>

Notice that S is on the x-axis, therefore the y-coordinate is "0".

Notice that S has the same x-value of R. The x-value of R is "a".

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3 years ago

Sam has softball practice every 3 days and drama lessons every 7 days. On what day will both occur?

sweet [91]

Answer:

the 21st day

Step-by-step explanation:

21 is 3 and 7's least common multiple

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3 years ago

Read 2 more answers

Kenya has 2 hours to make a 104 mile trip. What rate must she average to make the trip in 2 hours? A) 50 mph B) 51 mph C) 52 mph

sattari [20]

C. 52 mph.
104\2 = 52

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3 years ago

At the end of a Pizza party 1/3 of a cheese pizza and 1/6 of a pepperoni pizza or left brand ate 1/2 of all the leftover pizza w

Zina [86]

Answer:

1/6

Step-by-step explanation:

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3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago