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bixtya [17]
3 years ago
8

The Green Line circles the station every 9 minutes. The red live circles the station every 6 minutes. If they leave the station

together, how long will it be until the next time that they leave the station together again?
Please explain

A) 15 minutes

B) 18 minutes

C) 36 minutes

D) 54 minutes
Mathematics
1 answer:
maria [59]3 years ago
4 0
D) Because if you do 9 *6 you get 54 minutes until the next time.



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Which of the following is an equivalent form of the compound inequality
blondinia [14]

Answer:

pls mark brainy

Step-by-step explanation:

option (d) is correct.

An equivalent form of the  given compound inequality −44 > −2x − 8 ≥ −8 is  −44 > −2x − 8 and −2x − 8 ≥ −8

Step-by-step explanation:

Given a compound inequality −44 > −2x − 8 ≥ −8

We have to write  an equivalent form of compound inequality.

Compound inequality  consists of two inequalities joined together and the solution is the intersection of each inequality.

Compound inequality has two sides the left hand side and right hand side we can solve them by taking each inequality one at a time.

For given compound inequality, −44 > −2x − 8 ≥ −8

we have

Left side of inequality as  −44 > −2x − 8

and right side of inequality as  −2x − 8 ≥ −8

Thus, option (d) is correct.

Thus, An equivalent form of the  given compound inequality −44 > −2x − 8 ≥ −8 is  −44 > −2x − 8 and −2x − 8 ≥ −8

3 0
3 years ago
What is the slope for this graph?*<br><br><br><br> (3,2)<br> |(1,2)<br> (-2,1)<br> (-1,2)
Ad libitum [116K]

Answer:

the slope is 0

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

4 0
3 years ago
State the intervals for which the given quadratic is positive and when it is negative.
goblinko [34]

Answer:

  • Positive at (-9, 2)
  • Negative at ( -oo, -9) or (2, + oo)

Step-by-step explanation:

<u>Given function</u>

  • y= -2x^2 - 14x + 36

<u>Getting zero's</u>

  • -2x^2 - 14x + 36 = 0
  • x^2 + 7x - 18 = 0
  • x = ( -7 ± √(49 +72))/2 = ( -7 ± 11)/2
  • x = - 9 and x = 2

<u>As the x^2 has negative coefficient, the function is positive between -9 and 2</u>

  • - 9 < x < 2 or
  • (-9, 2)

<u>And it is negative at:</u>

  • x < -9 and
  • x > 2
  • or
  • ( -oo, -9) or (2, + oo)

3 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!
olga55 [171]
I believe the answer is 45.
6 0
3 years ago
Read 2 more answers
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