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Answer:
see explanation
Step-by-step explanation:
the equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Given the equation in standard form : ax² + bx + c : a ≠ 0
then the x-coordinate of the vertex is
= -
j(x) = x² - 12x + 7 is in standard form
with a = 1, b = - 12 and c = 7, hence
= -
= 6
substitute x = 6 into j(x) for y- coordinate
y = 6² - 12(6) + 7 = 36 - 72 + 7 = - 29
vertex = (6, - 29 ) and
j(x) = (x - 6)² - 29 ← equation in vertex form