Hey! So, the answer is the letter B.
It’s the square root of 2 (100%)
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(a) someone over 55
mean, mu = 22
standard deviation, sigma = 2
X=19
Z(X)=(X-mu)/sigma=(19-22)/2=-1.5
P(x>X)=1-P(x<X)=1-0.0668072=0.9331928
Therefore probability for a 55-year old to find a job in over 19 weeks is 0.9332
Answer:
D. p = 6.25h
Step-by-step explanation:
6.25 (2) = p 12.50
6.25 (4) = p 25.00
6.25 (6) = p 37.50
6.25 (8) = p 50.00