Question

For f(x)=4x+1 and g(x)=x^2-5, find (f+g)(x)

Answer 1

For this case we have the following functions:

$f (x) = 4x + 1\\g (x) = x ^ 2-5$

We must find $(f + g) (x).$ By definition we have to:

$(f + g) (x) = f (x) + g (x)$

So:

$(f + g) (x) = (4x + 1) + (x ^ 2-5) = 4x + 1 + x ^ 2-5 =$

Different signs are subtracted and the major sign is placed.

$(f + g) (x) = x ^ 2 + 4x-4$

Answer:

$(f + g) (x) = x ^ 2 + 4x-4$