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Andrews [41]
4 years ago
6

What is the simplest way for 16/35

Mathematics
2 answers:
Brums [2.3K]4 years ago
5 0

Answer:

16/35

Step-by-step explanation:

This is the simplest way.

kolezko [41]4 years ago
4 0

Answer:

16/2 and 35/2 then divide the two answers you get and thats you answer

Step-by-step explanation:

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ASAP GEO PROBLEM HELP NEEDED QUICK
olya-2409 [2.1K]

Answer:

See below.

Step-by-step explanation:

The converse of the Pythagorean Theorem tells us that if the sum of the square of the two shorter lengths is equivalent to the square of the longest length, then the triangle is indeed a right triangle.

We have the side lengths (x²-1), (2x), and (x²+1).

We can see that our hypotenuse will be (x²+1), since it will always yield the largest value for x.

So, we can use the Pythagorean Theorem:

a^2+b^2=c^2

Substitute (x²-1) and (2x) for a and b, and substitute (x²+1) for c:

(x^2-1)^2+(2x)^2\stackrel{?}{=}(x^2+1)^2

Square each expression:

(x^4-2x^2+1)+(4x^2)\stackrel{?}{=}(x^4+2x^2+1)

Combine like terms:

x^4+(-2x^2+4x^2)+1\stackrel{?}{=}(x^4+2x^2+1)

Add:

x^4+2x^2+1\stackrel{\checkmark}{=}x^2+2x^2+1

We can see that the resulting equations are equivalent, proving that the triangle is indeed a right triangle.

And we're done!

4 0
3 years ago
(-1)\times (-(-2)) \times (-(-(-3))) \times (-(-(-(-4)))
Semenov [28]

Answer:  the answer that I got was 24

Step-by-step explanation:

I hope it’s right and it helps!

7 0
3 years ago
Read 2 more answers
A student solved the equation 7 = 3(t - 1) - 2(t - 3) as shown below. Assume there is a value for t that satisfies the equation.
GalinKa [24]

Answer: 7

Step-by-step explanation: You first distribute 3, and -2. This gets you 7 = 3t -3 -2t +3. Then you add like terms which gets you, 7 = t.

3 0
4 years ago
Question 21 of 25
Korvikt [17]

Answer:

12

Step-by-step explanation:

Coefficient is the number before the variable

3 0
3 years ago
Consider M, N, and P. collinear points on MP.
Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}

2. Point N lies to the right from point P, then MP + PN = MN.  Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}

3 0
3 years ago
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